Write an equation of the line that is parallel to -x + y = 5 and passes through the point (2, -5 a) y = x - 7 b) y = x - 5 c) y = x - 3 d) y = -x - 3

A

Step-by-step explanation:

We fail to reject the null hypothesis that the average content of containers of the lubricant is 10 liters, this at the significance level of 0.01

Step-by-step explanation:

Let X be the random variable that represents the content of a container of the lubricant. We have observed n = 10 values, = 10.06 and s = 0.2459. We assume that X is normally distributed.

We have the following null and alternative hypothesis

vs (two-tailed alternative)

We will use the test statistic  

because we have a small sample size. And the observed value is

if is true, then T has a t distribution with n-1 = 9 degrees of freedom.

The rejection region for a two-tailed alternative and a significance level of 0.01 is given by RR = {t | t < -3.2498 or t > 3.2498}, where 3.2498 is the value such that there is an area of 0.005 above this number and under the density of the t distribution with 9 df.

Because the observed value 0.7716 does not fall inside RR, we fail to reject the null hypothesis.