Mathematics: Write the equation of a line perpendicular to y =-1/ 8x that passes through point (-12, - 4) point slope form, thanks :)

Write the equation of a line perpendicular to

Ответ:

jor66

06.02.2022

y+4=3(x+12)

Step-by-step explanation:

Perpendicular lines have opposite reciprocal slopes, meaning that if you had $\frac{4}{3}$ , the opposite would change the sign: $-\frac{4}{3}$ , and the reciprocal would flip the fraction: $\frac{-3}{4}$

We can find the slope of the line perpendicular to the line $y=-\frac{1}{3}x-8$ by finding the opposite reciprocal of -1/3 (slope is the coefficient of x).

Opposite: $\frac{1}{3}$ Change the sign Reciprocal: $\frac{3}{1}=3$ Flip the fraction

Now we have the slope of the line and a point that the line passes through. We are now able to use point-slope form.

Point-slope form:

Where $(x_1, \ y_1)$ are the coordinates of a point that the line passes through, and is the slope of the line.

Substitute (-12, -4) and m = 3 into the point-slope equation.

Distribute the negative sign inside the parentheses.

This is the equation of the line perpendicular to y = -1/3x - 8 and that passes through point (-12, -4) in point-slope form.

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Write the equation of a line perpendicular to y =-1/ 8x that passes through point (-12, - 4) point slope form, thanks :)

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