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sophiaa23
02.02.2020 •
Mathematics
Write the equation of the line that is perpendicular to the line 8y−16=5x through the point (5,-5).
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Ответ:
y = -(8/5)x + 3
Step-by-step explanation:
Step 1: Rewrite the given equation into slope-intercept form by solving for y
8y−16=5x
8y = 5x + 16
y = (5/8)x + 2
Perpendicular lines have slopes that are opposite reciprocals of each other. That means you take the slope, flip the fraction, and change the sign.
Here our given line is y = (5/8)x + 2 so the slope 5/8
The opposite reciprocal of 5/8 is -8/5
We set up the equation
y = -(8/5)x + b
we are given a point (x, y) of (5, -5), so plug that in and solve for b
-5 = -(8/5)(5) + b
-5 = -8 + b
3 = b
So our equations is y = -(8/5)x + 3
Ответ:
D)More people entered through Gate A than through Gate B.
Step-by-step explanation:
Gate A = 3(x + 1)
Gate B = 3x + 1
x = 1
Gate A = 3(1 + 1)
= 3(2)
=6
Gate B = 3x + 1
= 3(1) + 1
= 4 + 1
hope this helps