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BigI80531
24.11.2019 •
Mathematics
Write the quadratic equation in standard form that
has x-intercepts at (-4/3,0) and (-3,0)
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Ответ:
y = a(x² + (13/3)x + 12/3)
Step-by-step explanation:
First use the equation in x-intercept form: y = a(x-r)(x-s)
Where r and s are the values for the x-intercept
Substitute the x-intercepts
y = a(x - (-4/3)) (x - (-3))
Simplify
y = a(x + (4/3)) (x + 3)
Distributive property for brackets:
y = a(x² + 3x + (4/3)x + 12/3)
Find common denominator in fractions to collect like terms
y = a(x² + (9/3)x + (4/3)x + 12/3)
y = a(x² + (13/3)x + 12/3)
We cannot solve for the "a" value without another point.
If given the other point, substitute it for x and y to solve for a.
Then rewrite the equation with the "a" value.
Ответ:
Its a i just took the test
Step-by-step explanation: