Mathematics: Write the standard form of the equation of the circle below. Center (0,-1) passes through the point (-1,-2)

Write the standard form of the equation of the

kashbaby

18.03.2022

x^2+(y+1)^2=2

Step-by-step explanation:

We use the formula for a circle with center at (0, -1), that goes through the (x, y) point (-1, -2):

$(x-0)^2 + (y-(-1))^2 = R^2\\Using \,\,\,point\,\,\,(-1, -2)\\(-1-0)^2+ (-2+1)^2 = 1 + 1 = 2 = R^2$

Therefore, the equation of this circle can be written as:

x^2+(y+1)^2=2

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juniorgutierrez997

01.04.2023

direct variation is y = kx where y would be the value of the number and x would be its position in the sequence, k is a constant

so for consecutive values y/x would be a constant k

In this case its not true becuse for example 3/1 = 3 and 6/3 = 2

so there is no direct variation here.

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