(x^2+1)(x-2)=x^3-2x^2+x-2
solve for x

Step 1: Subtract x^3 from both sides.x^3−2x^2+x−2−x^3=x^3−2x^2+x−2−x^3−2x^2+x−2=−2x^2+x−2

Step 2: Add 2x^2 to both sides.−2x^2+x−2+2x^2=−2x^2+x−2+2x^2x−2=x−2

Step 3: Subtract x from both sides.x−2−x=x−2−x−2=−2

Step 4: Add 2 to both sides.−2+2=−2+20=0

All real numbers are solutions.

The formula used will be:

tan 42° = y/115

Step-by-step explanation:

Lets simplify the the question.

We have a boat which is situated at 115 meters away from a light house. It forms the base of the right angled triangle.

We need to find the distance from the bottom of the light house to the top of the light house. This distance is the height of the lighthouse, which forms the perpendicular side of the right angled triangle.

The distance between boat and top of the lighthouse is unknown, it forms the hypotenuse.

The angle of elevation, which is the angle between base and hypotenuse, is given as 42°.

The right angled formed is shown below.

We know that

tanθ = Perpendicular / Base

tan42 = height / 115

If height= y

tan 42° = y/115

Solve for y.

y = 103.55 meters