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xojade

07.07.2019 •

Mathematics

X^2-4y^2=0 a.(x+4y)(x-y) b. (x-4y)(x+y) c. (x+2y)(x-2y) d. (x-2y)(x-2y)

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Ответ:

ayshajabeenmeox5jrh

11.03.2022

$x^{2}$ -4 $y^{2}$ = 0

Solution

Here we have to find the factors.

$x^{2} - 4y^{2} = 0$

Here we can write 4y^2 as (2y)^2

$x^{2} - (2y)^{2} = 0$

Now we have to use the formula, a^2 - b^2 = (a + b)(a - b)

Here a = x and b = 2y

Therefore, we get

(x + 2y)(x -2y)

Hence, the answer isC. (x + 2y)(x -2y)

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Ответ:

Chloe0095

19.04.2023

thanks amajon!!! have a great day

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