krystalhurst97
18.04.2020 •
Mathematics
X^2+y^2-10x-16y+53=0
What is the center of the circle?
What is the radius of the circle?
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Ответ:
Step-by-step explanation:
hello : Completing The Square
X²+y²-10x-16y+53=0 means : (x²-10x+25-25)+(y²-16y+16-16)+53 =0
(x²-10x+25)-25)+(y²-16y+64)-64+53 =0
(x+5)²+(y-8)² -25-64+53=0
(x+5)²+(y-4)² = 6² standard form
the center is (-5 , 4) and the radius : 6
Ответ: