Mathematics: X- 7 = -2x - 11a. 4b. -14c. -4d. 14

X- 7 = -2x - 11a. 4b. -14c. -4d. 14 - id7211414414565569, adantrujillo1234

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24.03.2022

The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

Step-by-step explanation:

Denote the events as follows:

F = a person with fibromyalgia

R = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

$P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}\\\\=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=0.183333\\\\\approx 0.1833$

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

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