wolfgirl4762
03.02.2020 •
Mathematics
X= cos(2t) and y = sin(2t)
find the second derivative
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Ответ:
dy/dt = 2cos(2t)
dx/dt = -2sin(2t)
dy/dx = 2cos(2t)/-2sin(2t) = -cot(2t)
d^y/dx^2 = d(-1/tan(2t))/dx = (tan(2t) * 0 - (-1)*2sec^2(2t))/tan^2(2t) = 2sec^2(2t)/tan^2(2t) = 2csc^2 (2t)
Ответ:
solving by factory:
4x^2-25=0
(2x-5)(2x+5)=0
x=-5/2 or 5/2