Mathematics: Xcubed - y cubed factor completely

Xcubed - y cubed factor completely - id203326, cuppykittyy

Ответ:

dhernandez081

10.03.2022

Mathematics

ANSWER

${x}^{3} - {y}^{3} = (x - y)[ {x}^{2} + xy + {y}^{2}]$

EXPLANATION

We want to factor:

${x}^{3} - {y}^{3}$

completely.

Recall from binomial theorem that:

$( {x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3}$

We make x³-y³ the subject to get:

${x}^{3} - {y}^{3} = ( {x - y)}^{3} + 3 {x}^{2} y - \:3x {y}^{2}$

We now factor the right hand side to get;

${x}^{3} - {y}^{3} = ( {x - y)}^{3} + 3 {x} y(x - y)$

We factor further to get,

${x}^{3} - {y}^{3} = (x - y)[( {x - y)}^{2} + 3 {x} y]$

${x}^{3} - {y}^{3} = (x - y)[ {x}^{2} - 2xy + {y}^{2} + 3 {x} y]$

This finally simplifies to:

${x}^{3} - {y}^{3} = (x - y)[ {x}^{2} + xy + {y}^{2}]$

0,0(0 оценок)

Ответ:

YoVeoAnime

23.12.2021

Mathematics

The answer to your question is the first option is correct

Step-by-step explanation:

Data

From the graph we get

Center = (0, 0)

Focus = (-7, 0) and (7, 0)

a = 12

c = 7

It is a horizontal ellipse

Formula

Process

1.- Calculate b

a² = b² + c²

b² = a² - c²

b² = 12² - 7²

b² = 144 - 49

b² = 95

2.- Substitution

3.- Conclusion

The first choice

0,0(0 оценок)

Xcubed - y cubed factor completely

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question