Mathematics: Y/1 = 36/x is this a direct variation or an inverse variation?

a 95% confidence interval for the proportion of all customers who have experienced a service interruption: (0.076, 0.127).Step-by-step explanation:Let p be the population proportion of all customers who have experienced a service interruption.Confidence interval for p:, where = sample proportion, n= sample size, z* = critical z-value.Given: n = 540z* = 1.96The required confidence interval:Hence, a 95% confidence interval for the proportion of all customers who have experienced a service interruption:...

Y/1 = 36/x is this a direct variation or an inverse

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daquanmcqueen77

07.11.2020

Mathematics

a 95% confidence interval for the proportion of all customers who have experienced a service interruption: (0.076, 0.127).

Step-by-step explanation:

Let p be the population proportion of all customers who have experienced a service interruption.

Confidence interval for p: $\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$ , where $\hat{p}$ = sample proportion, n= sample size, z* = critical z-value.

Given: n = 540

$\hat{p}=\dfrac{55}{540}=0.102$

z* = 1.96

The required confidence interval:

$0.102\pm (1.96)\sqrt{\dfrac{0.102(1-0.102)}{540}}\\\\=0.102\pm (1.96)(0.013024)\\\\=0.102\pm$$0.02552704\\\\=(0.102-$$0.02552704, 0.102+0.02552704)\\\\\approx(0.076, 0.127)$

Hence, a 95% confidence interval for the proportion of all customers who have experienced a service interruption: (0.076, 0.127).

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Y/1 = 36/x is this a direct variation or an inverse variation?

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