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Kimb6863
30.06.2019 •
Mathematics
Y=x^3 + 2x^2 - 5x - 6; (x+1) show all work
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Ответ:
y=(x+1)^3 + 2(x+1)^2 -5(x+1) -6
y= x^3 +1 +2x^2+2-5x-5-6
y=x^3+2x^2-5x -10
Ответ:
Square Root of 41 to the nearest tenth, means to calculate the square root of 41 where the answer should only have one number after the decimal point.
Here are step-by-step instructions for how to get the square root of 41 to the nearest tenth:
Step 1: Calculate
We calculate the square root of 41 to be:
√41 = 6.40312423743285
Step 2: Reduce
Reduce the tail of the answer above to two numbers after the decimal point:
6.40
Step 3: Round
Round 6.40 so you only have one digit after the decimal point to get the
6.4
To check that the answer is correct, use your calculator to confirm that 6.42 is about 41.
Step-by-step explanation: