Y=x²+4x-3 y=5x+3 solve the simultaneous equation​

(-2, -7) or (3, 18)

Step-by-step explanation:

Start with your 2 equations

y = x^2 + 4x - 3

y = 5x + 3

Because both equal y, we substitute:

x^2 +4x -3 = 5x+ 3

x^2 - x - 6 = 0

Factor:

(x + 2) (x - 3) = 0

Solutions for x: -2 or 3 since if either of the numbers in parentheses is 0, the equation is 0 (0* anything = 0).

Then plug -2 in for x in either equation:

y = 5* -2 + 3

y = -7

So ( -2, -7) is a solution.

Plug 3 in for x in either equation:

y = 5*3 + 3

y = 18

So ( 3 , 18) is a solution.

Hope that helps, let me know if I did anything wrong!

(- 2, - 7 ) and (3, 18 )

Step-by-step explanation:

Given the 2 equations

y = x² + 4x - 3 → (1)

y = 5x + 3 → (2)

Substitute y = x² + 4x - 3 into (2)

x² + 4x - 3 = 5x + 3 ( subtract 5x + 3 from both sides )

x² - x - 6 = 0 ← in standard form

(x - 3)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x - 3 = 0 ⇒ x = 3

Substitute these values into (2) for corresponding values of y

x = - 2 : y = 5(- 2) + 3 = - 10 + 3 = - 7 ⇒ (- 2, - 7 )

x = 3 : y = 5(3) + 3 = 15 + 3 = 18 ⇒ (3, 18 )