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14.01.2020 •
Mathematics
Y=x2 +6x-2
write each quadratic in vertex form by completing the square. then identify the quadratic’s turning point
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Ответ:
see explanation
Step-by-step explanation:
The equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Given
y = x² + 6x - 2
To complete the square
add/ subtract ( half the coefficient of the x- term )² to x² + 6x
y = x² + 2(3)x + 9 - 9 - 2
= (x + 3)² - 11 ← in vertex form
with (h, k) = (- 3, - 11 )
Turning point = (- 3, - 11 )
Ответ: