Mathematics: You are given e=0.020 a confidence level of 90% and a sample portion of 85% from a recent survey find the minimum sample size to estimate a population proportiona.1225b.259c.5751d.863

Power of 10. Times everything by 10. So example- 10x10 is 100...

You are given e=0.020 a confidence level of 90% - id002090667127, emilycarmadelle6653

kaitherusher

12.03.2022

Option d)863

Step-by-step explanation:

Given that

e=Margin of error = 0.020

Confidence level =90%

zcritical for 90% =1.645

We have margin of error = 1.645 (std dev)/sq rt n

where n = sample size

Since p = 0.85

Std error = $\sqrt[2]{\frac{pq}{n} } =\sqrt[2]{\frac{0.85(0.15)}{n} } \\=\frac{0.357}{\sqrt[2]{n} }$

Substitute in margin of error to get

0.020=1.645(0.357)/sqrt n

Simplify to get

n=862.54

Since n cannot be in decimal round off to the next integer

n =863

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