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tamiawilliams3pe55hs
14.10.2019 •
Mathematics
You can approximate e by substituting large values for n into the expression
a) (1-n)^1/n
b) (1+1/n)^n
c) (1-1/n)^n
d) (1+n)^1/n
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Ответ:
You can test this:
(1 + (1/50000))^50000 = 2.718
So the answer is B
Ответ:
most probablynot needed here