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Haddixhouse5273
09.11.2020 •
Mathematics
You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of the can (radius and height) will use the least amount of material?(Hint: The lightest can will be the can with the smallest surface area.)
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Ответ:
Step-by-step explanation:
Given
Represent volume with v, height with h and radius with r
Required
Determine the values of h and r that uses the least amount of material
Volume is calculated as:
Substitute 432π for V
Divide through by π
Make h the subject:
Surface Area (A) of a cylinder is calculated as thus:
Substitute
for h in ![A=2\pi rh+2\pi r^2](/tpl/images/0881/8736/d110f.png)
Factorize:
To minimize, we have to differentiate both sides and set![A' = 0](/tpl/images/0881/8736/a6160.png)
Set![A' = 0](/tpl/images/0881/8736/a6160.png)
Divide through by![2\pi](/tpl/images/0881/8736/773dc.png)
Cross Multiply
Divide through by 2
Take cube roots of both sides
Recall that:
Hence, the dimension that requires the least amount of material is when
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