laylaaaaah2054
01.08.2019 •
Mathematics
You invested $11,000 in two accounts paying 8% and 9% annual interest, respectively. if the total interest earned for the year was $980, how much was invested at each rate?
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Ответ:
0.08 x + 0.09 (11000 - x) = 980 Now solve for x which is the amount invested at 8%
0.08x + 990 - 0.09x = 980
- 0.01x = 980 - 990 = -10
x = -10 / -0.01
x = 1000
So he invest 1000 in 8% and 10000 at 9%
Ответ:
he invest 1000 in 8% and 10000 at 9%
Step-by-step explanation:
<3
Ответ:
-20
Step-by-step explanation: