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gobbler80
07.04.2020 •
Mathematics
You need 1045 mL of a 70% alcohol solution. On hand, you have a 5% alcohol mixture. How much of the 5% alcohol mixture and pure alcohol will you need to obtain the desired solution?
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Ответ:
x=330 ml
y=715 ml
Step-by-step explanation:
If we let x = the amount of 5% solution and y = the amount of pure alcohol, we can set up that;
0.05x + y is the amount of alcohol in our resulting mixture, and x+y is the total amount in our resulting mixture (which we know is 1045 mL)
Now, we also know that:
(0.05x + y)/0.7 = 1045
Thus,
If we simplify this we come up with:
0.05x + y = 731.5 - - - - (eq1)
and we know x + y = 1045 - - - (eq2)
Let's subtract eq(1) to eq(2) to obtain;
0.95x = 1045 - 731.5
0.95x = 313.5
x = 313.5/0.95
x = 330 ml
Put x = 330 ml for y in eq 2 to get;
330 + y = 1045
y = 1045 - 330
y = 715ml
So,
x=330 ml
y=715 ml
Ответ:
Step-by-step explanation:
we have
For![m=5.n=4](/tpl/images/1004/6986/7eb30.png)
substitute the values of m and the value of n in the equation
so