You purchased 8 pounds 10 ounces of candy from a candy shop. you want to split it equally among 3 classrooms at a local school.

Each classroom gets exactly 46 oz.

Step-by-step explanation:

In order to find that, start by converting the amount to oz. We can do this by multiplying the amount of pounds by 16 and then adding the ounces.

8 * 16 = 128

128 + 10 = 138 oz

Now we can divide that amount by 3 to get the amount per classroom.

138/3 = 46 oz per classroom.

Andre has more money than Bob.  If Andre gave Bob $20, they would have the same amount.  While if Bob gave Andre $22, Andre would then have twice as much as Bob.  How much does each one actually have?

Step-by-step explanation:

Here is the first sentence:

"If Andre gave Bob $20, they would have the same amount."

Algebraically:

1)   x − 20 = y + 20.

(Andre -- x -- has the same amount as Bob, after he gives him $20.)

Here is the second sentence:

"While if Bob gave Andre $22, Andre would then have twice as much

as Bob."

Algebraically:

2)   x + 22 = 2(y − 22).

(Andre has twice as much as Bob -- after Bob gives him $22.)

To solve any system of two equations, we must reduce it to one equation in one of the unknowns.  In this example, we can solve equation 1) for x --

x − 20=y + 20

 implies  x=y + 40

-- and substitute it into equation 2):

y + 40 + 22=2(y − 22).

      That is,

y + 62=2y − 44,

y − 2y=− 44 − 62,

according to the techniques of Lesson 9,

−y=−106

y=106.

Bob has $106.  Therefore, according to the exression for x, Andre has

106 + 40 = $146.

I hope this helps u! :D