You reflect triangle PQR, with coordinates P(-4, -4), Q(-1, -3), and R(-3, -1), across the x-axis, across the y-axis, and across the x-axis again to form triangle P′Q′R′. After these reflections, the coordinates of P′ will be ( , ).

  P'( 4, -4)

Step-by-step explanation:

The double reflection across the x-axis does nothing, so the net effect is a single reflection across the y-axis. That effect is to negate the x-coordinate:

  reflection across y-axis: (x, y) ⇒ (-x, y)

  Then P(-4, -4) ⇒ P'(4, -4)

(0.5, 5.5)

Step-by-step explanation:

So we know that one point is (-4, 6) and the other point is (3, 5). Also we know that Diagonals of a rhombus intersect at their midpoints.  

For that reason, the point is:

x = (3 -4)/2=0.5

y=(5+6)/2 = 5.5

Then, the response is: (0.5, 5.5)