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payshencec21
21.01.2020 •
Mathematics
You toss three 6-sided dice and record the sum of the three faces facing up. a) describe precisely a sample space s for this experiment. b) what is the probability that the sum is 16 or more? c) what is the probability the sum is exactly 4 or 5? d) what is the probability the sum is less than 17?
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Ответ:
a.)Sample space means all possible outcomes, since we know the dice are 6 face, then the sample space becomes all possible outcomes when we toss the die.
b.) 9/216
c.) 9/216
d.) 212/216
Step-by-step explanation:
Sample space means all possible outcomes, since we know the dice are 6 face, then the sample space becomes all possible outcomes when we toss the die.
[1,1,1] [1,1,2] [1,1,3] [1,1,4] [1,1,5] [1,1,6]
[1,2,1] [1,2,2] [1,2,3] [1,2,4] [1,2,5] [1,2,6],
[1,3,1] [1,3,2] [1,3,3] [1,3,4] [1,3,5] [1,3,6]
[1,4,1] [1,4,2] [1,4,3] [1,4,4] [1,4,5] [1,4,6]
[1,5,1] [1,5,2] [1,5,3] [1,5,4] [1,5,5] [1,5,6]
[1,6,1] [1,6,2] [1,6,3] [1,6,4] [1,6,5] [1,6,6]
[2,1,1] [2,1,2] [2,1,3] [2,1,4] [2,1,5] [2,1,6]
[2,2,1] [2,2,2] [2,2,3] [2,2,4] [2,2,5] [2,2,6],
[2,3,1] [2,3,2] [2,3,3] [2,3,4] [2,3,5] [2,3,6]
[2,4,1] [2,4,2] [2,4,3] [2,4,4] [2,4,5] [2,4,6]
[2,5,1] [2,5,2] [2,5,3] [2,5,4] [2,5,5] [2,5,6]
[2,6,1] [2,6,2] [2,6,3] [2,6,4] [2,6,5] [2,6,6]
[3,1,1] [3,1,2] [3,1,3] [3,1,4] [3,1,5] [3,1,6]
[3,2,1] [3,2,2] [3,2,3] [3,2,4] [3,2,5] [3,2,6],
[3,3,1] [3,3,2] [3,3,3] [3,3,4] [3,3,5] [3,3,6]
[3,4,1] [3,4,2] [3,4,3] [3,4,4] [3,4,5] [3,4,6]
[3,5,1] [3,5,2] [3,5,3] [3,5,4] [3,5,5] [3,5,6]
[3,6,1] [3,6,2] [3,6,3] [3,6,4] [3,6,5] [3,6,6]
[4,1,1] [4,1,2] [4,1,3] [4,1,4] [4,1,5] [4,1,6]
[4,2,1] [4,2,2] [4,2,3] [4,2,4] [4,2,5] [4,2,6],
[4,3,1] [4,3,2] [4,3,3] [4,3,4] [4,3,5] [4,3,6]
[4,4,1] [4,4,2] [4,4,3] [4,4,4] [4,4,5] [4,4,6]
[4,5,1] [4,5,2] [4,5,3] [4,5,4] [4,5,5] [4,5,6]
[4,6,1] [4,6,2] [4,6,3] [4,6,4] [4,6,5] [4,6,6]
[5,1,1] [5,1,2] [5,1,3] [5,1,4] [5,1,5] [5,1,6]
[5,2,1] [5,2,2] [5,2,3] [5,2,4] [5,2,5] [5,2,6],
[5,3,1] [5,3,2] [5,3,3] [5,3,4] [5,3,5] [5,3,6]
[5,4,1] [5,4,2] [5,4,3] [5,4,4] [5,4,5] [5,4,6]
[5,5,1] [5,5,2] [5,5,3] [5,5,4] [5,5,5] [5,5,6]
[5,6,1] [5,6,2] [5,6,3] [5,6,4] [5,6,5] [5,6,6]
[6,1,1] [6,1,2] [6,1,3] [6,1,4] [6,1,5] [6,1,6]
[6,2,1] [6,2,2] [6,2,3] [6,2,4] [6,2,5] [6,2,6],
[6,3,1] [6,3,2] [6,3,3] [6,3,4] [6,3,5] [6,3,6]
[6,4,1] [6,4,2] [6,4,3] [6,4,4] [6,4,5] [6,4,6]
[6,5,1] [6,5,2] [6,5,3] [6,5,4] [6,5,5] [6,5,6]
[6,6,1] [6,6,2] [6,6,3] [6,6,4] [6,6,5] [6,6,6]
b.) Probability that the sum is 16 or more is
Pr[4,6,6] + pr[5,5,6] + pr [ 5,6,5] + pr [5,6,6] + pr [6,5,5] + pr [6,5,6] + pr [6,6,4] + pr[6,6,5] + pr [6,6,6]
Becomes:
[1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ = 9/216
Probability that the sum is 4 or 5 is
Pr [ 1,1,2] or pr[1,2,2] or pr [1,1,3] or pr [1,2,1] or pr[2,1,2] or pr[1,3,1] or pr[3,1,1] or pr[2,1,1] or pr[2,2,1]
Becomes:
[1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ = 9/216
Probability that the sum is less than 17
We take it as:
1- probability that the sum is 17 and above.
Now probability that the sum is 17 and above becomes
pr[5,6,6] or pr[6,5,6] or pr[6,6,5] or pr[6,6,6]
= [1/6]³ + [1/6]³ + [1/6]³ + [1/6]³ = 4/216
Hence, probability that the sum is less than 17 becomes:
1-4/216 = 212/216.
Ответ: