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anthony983
18.11.2019 •
Mathematics
You work for the national weather service and are asked to study the average daily temperatures in anchorage, alaska. you calculate the mean of the average daily temperatures for each month. you decide to place the information on a graph in whwill correspond to the month 0 as indicated by the dot on the input scale. ich the date is the input and the temperature is the output. you also decide that january 1950
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Ответ:
because want you to plot a point for "July 1963 was 63 degrees Fahrenheit" so that's in the positive temp region
so the correct option will be 1 and it is
D
hope it helps
Ответ:
I added a screenshot with the complete question
Answers:
a. The average daily temperature for January 1990 will be in the third quadrant.
b. The average daily temperature for July 2005 will be in the first quadrant.
c. The average daily temperature for July 1995 will be in second quadrant.
d. The average daily temperature for January 2009 will be in the fourth quadrant.
Explanation:
Now, before we begin, remember that:
In the coordinates plane:
1st quadrant has positive x value and positive y value
2nd quadrant has negative x value and positive y value
3rd quadrant has negative x value and negative y value
4th quadrant has positive x value and negative y value
Check the second attachment.
Now, for the given, we have:
The x-axis represents the month
The y-axis represents the temperature
The origin point represents month January 2000
Part 1: Average temperature in January 1990:
January 1990 precedes January 2000. This means that January 1990 will lie on the -ve x-axis
The average temperature in January 1990 was given as -13°F. This means that the average temperature will lie on the -ve y-axis
Combining the two, we will find that both x and y values are negative which means that the point will lie in the third quadrant
Part 2: Average temperature in June 2005:
June 2005 is after January 2000. This means that June 2005 will lie on the +ve x-axis
The average temperature in June was given as 62°F. This means that the average temperature will lie on the +ve y-axis
Combining the two, we will find that both x and y values are positive which means that the point will lie in the first quadrant
Part 3: Average temperature in July 1995:
July 1995 precedes January 2000. This means that July 1995 will lie on the -ve x-axis
The average temperature in July 1995 was given as 63°F. This means that the average temperature will lie on the +ve y-axis
Combining the two, we will find that the x-value is negative while the y-value is positive which means that the point will lie in the second quadrant.
Part 4: Average temperature in January 2009:
January 2009 is after January 2000. This means that January 2009 will lie on the +ve x-axis
The average temperature in January 2009 was given as -13°F. This means that the average temperature will lie on the -ve y-axis
Combining the two, we will find that the x-value is positive while the y-value is negative which means that the point will lie in the fourth quadrant.
The place of each point (a, b, c and d) is shown on the first attachment.
Hope this helps :)
Ответ:
2. You can set up the relation as a table of ordered pairs. Then, text to see if each element in the domain is matched with exactly one element in the range . if so you have a function
3. The domain is the set of all possible x-values which will make the function "work" and will output real y- values .When finding the domain , remember :the denominator (bottom) of a fraction cannot be zero .
4.