Physics: 0.5000 kg of water at 35.00 degrees celsius is cooled, with the removal of 6.300 e4 j of heat. what is the final temperature of the water? specific heat capacity of water is 4186 j/(kg co).remember to identity all of your data, write the equation, and show your work.

The answer is 60 inches of snow ...

0.5000 kg of water at 35.00 degrees celsius is cooled,

ashleyprescot05

14.03.2022

Answer : The final temperature of the water is 65.10^oC

Explanation :

Formula used :

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat released = $6.300\times 10^{4}J$

m = mass of water = 0.5000 kg

c = specific heat of water = 4186J/kg^oC

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = 35.00^oC

Now put all the given values in the above formula, we get:

$6.300\times 10^{4}J=(0.5000kg)\times (4186J/kg^oC)\times (T_{final}-35.00)^oC$

$T_{final}=65.10^oC$

Therefore, the final temperature of the water is 65.10^oC

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