1) If a bus travelling at 20 m/s is subject to a steady deceleration of 5 m/s2, how long will it take to come to rest?
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Ответ:
Bus will take 4 seconds before it comes to rest.
Explanation:
Initial Velocity of bus = u = 20 ms⁻¹
Final Velocity of bus = v = 0 ms⁻¹
Deceleration of bus = a = -5 ms⁻²
Time taken by bus before it comes to rest = t = ?
Using the equation formula
a = (v - u)/t
-5 = (0 - 20) / (t)
t = -20/-5
t = 4 sec
Therefore, Bus will take 4 seconds before it comes to rest.
Ответ:
The answers are 1,4,5,6,7.
I took the test.