2.09 j> g °c, and that of steam is 2.01 j> g °c. 72. how much heat (in kj) is evolved in converting 1.00 mol of at - 10.0 °c, to steam at 110.0 °c? the heat capacity of ice is ## 2.01 j> g °c, and that of ice is 2.09 j> g °c. phase diagrams steam at 145 °c to ice at - 50 °c? the heat capacity of steam is ##

1,54.95KJ

2. phase diagram can be found as attached

Explanation:

Definition of terms

Heat is the degree of hotness or coldness in a body

Specific heat capacity is the amount of heat to raise one kg mass of a substance by 1 degree rise in temperature

How much heat (in kJ) is evolved in converting 1.00 mol of iceat - 10.0 °C, to steam at 110.0 °C?

we take it step by step

the heat needed to raise ice from -10 to 0C

Q=mcdT

mass=mole*relative molecular mass of water

mass (g)=1*18g/mol

mass=18g

Q=18*2.1*(0-(-10)=378J

2. the heat of fusion of ice

Qf=mlf

Qf=18*334J/g

Qf=6012J

3. heat to take water from 0c to 100c

Q=18*4.18*(100)

7524J

4. heat of vapourization

Qv=mLv

Qv=18*2260=40680J

5. heat to raise the steam from 0c to 110c

Q=mCsteam*dT

Q=18*2.01*(110-100)

Q=361.8J

add up all the heat evolved

378+6012+7524+40680+361.8

=54955.8

54.95KJ

The procedure that Tonya utilizes should be that she moves a magnet into a coil of wire in a closed circuit. This will induce an EMF in the electric coil, which is directly proportional to the rate of change of flux. This is in accordance to Faraday's Law of Electromagnetic Induction. Moreover, the EMF produced will be in the direction opposing the movement of the magnet.