kalcius9698
17.07.2019 •
Physics
2)a velocity vector has components 36 m/s westward and 22 m/s northward. what are the magnitude and direction of this vector?
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Ответ:
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| a | = √ ( 22² + 36² ) = √ ( 484 + 1296 ) = √ 1780 = 42.19 m/s
The direction:
tan α = 22/36 = 0.61111
α = tan^(-1) 0.61111 = 31.43 ° = 31° 26`
The magnitude is 42.19 m/s and the direction is 31° 26`north from west.
Ответ:
8.575 m
Explanation:
speed = distance/time
distance -- 2d
343 = 2d/0.05
2d = 17.15
d = 17.15/2
d = 8.575
Thenks and mark me brainliest :))