6. starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. the car travels at a constant rate of 53 miles per hour. the distance of the car from the checkpoint is given by d = |1.5 – 53t|. at what times is the car 0.1 miles from the checkpoint? calculate your answer in seconds.
95.1s and 108.7s
10.2s and 101.9s
108.7s and 10.2s
95.1s and 10.2s

For the answer to the question above, 

To be 0.1 miles away from the check point ,
 the car has to travel 1.4 miles OR 1.6 miles. 

53 miles = 60 minutes 

1.4 miles = 1.4 / 53 X 60 = 1.5849056 minutes OR 95.1 seconds 

1.6 miles = 1.6 /53 X 60 = 1.8113207 minutes OR 108.7 seconds 
So the answer is 95.1s and 108.7s
I hope my answer helped you

1.97*10^14 W/m^2

Explanation:

To find the intensity of the light emitted by Betelgeuse you taken into account that the light from Betelgeuse expands spherically in space.

You use the following formula:

    (1)

I: intensity of light

r: distance from Betelgeuse to the exoplanet = (1/2)*7.5*10^10m

P: power = 100,000*3.486*10^31 W

By replacing the values of the parameters in (1) you obtain: