7. if silicon-32 has a decay chain with the following steps:
step #1 - alpha particle
step #2 - beta particle
what is the final radioactive isotope left at the end of this decay chain?
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Ответ:
Aluminium-28
Explanation:We are given;
Silicon-32
it undergoes a decay chain starting with alpha decay then followed by beta decay.
We need to know that when a radioactive isotope undergoes alpha decay its mass number decreases by 4 while the atomic number decreases by 2.When its a beta decay the mass number remains unchanged while atomic number increases by 1.In this case;Silicon-32 has an atomic number 14 and mass number 32.
#1. Alpha decay
Si-32 undergoes alpha decay to form a radioisotope with a mass number 28 and atomic number 12.That is; ³²₁₄Si → ²⁸₁₂X + ⁴₂He
#2. Beta decay
The radioisotope formed then undergoes beta decay to form a radioisotope with a mass number 28 and atomic number 13.That is;
²⁸₁₂X → ²⁸₁₃Y + ⁴₂He
Therefore, the radioisotope formed after the two decay at the end of decay chain is Al-28.Ответ:
D, The frequency of her voice matches the natural frequency of the glass.
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