Physics: 7. the according to wien’s law (λmax = 3×106/t), what is the temperature of the radiation? recall that to use this formula, the wavelength must be in nanometers (1nm = 10−9 m) and the temperature will be in kelvin.

7. the according to wien’s law (λmax = 3×106/t),

Ответ:

KillerSteamcar

15.03.2022

Physics

According to Wien’s Law:

$\lambda_{peak} = \frac{2.9 \times 10^{6} }{T(K)}$

where;

$\lambda_{peak}$ is the wavelength

T(K) is the temperature in Kelvin

Putting the values given in the above equation:

${T(K)} = \frac{2.9 \times 10^{6} }{\lambda_{peak}}$

${T(K)} = \frac{2.9 \times 10^{6} }{3 \times 10^{3}}}$

T(K) = 0.966× $10^{3}$

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Ответ:

corinaartsy

10.09.2020

Physics

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7. the according to wien’s law (λmax = 3×106/t), what is the temperature of the radiation? recall that to use this formula, the wavelength must be in nanometers (1nm = 10−9 m) and the temperature will be in kelvin.

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