Physics: A 0.05kg dart is thrown at and sticks into a 0.4 kg block hanging on a string. After the collision the block and dart swing in a circular arc rising 0.1m vertically. What must the speed have been just after the collision

A 0.05kg dart is thrown at and sticks into a 0.4 - id0050410442621, helloitschump0vfdz

genyjoannerubiera

17.03.2022

v = 1.4 m /s

Explanation:

We shall apply law of conservation of mechanical energy

The kinetic energy of dart and block is converted into potential energy of both dart and block .

1 /2 (m+M) v² = ( m +M) gH

.5 x v² = 9.8 x .1

= v² = 1.96

v = 1.4

v = 1.4 m /s

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amber3687

11.05.2020

a) $x=\dfrac{\text{Total amount}}{\text{Number of tickets}}\\\\x=\dfrac{930.75}{25}$

b) $37.23

Step-by-step explanation:

Since we have given that

Total amount raised by a theatre company = $930.75

Number of floor seat tickets = 25

We need to find the equation with a variable that can be solved to correctly find the price of each ticket.

Let the price of each ticket be 'x'.

so, Part A becomes,

$x=\dfrac{\text{Total amount}}{\text{Number of tickets}}\\\\x=\dfrac{930.75}{25}$

Part B:

Value of x be

$x=\dfrac{930.75}{25}=\$37.23$

Hence, a) $x=\dfrac{\text{Total amount}}{\text{Number of tickets}}\\\\x=\dfrac{930.75}{25}$

b) $37.23

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