mollycompton04
06.10.2021 •
Physics
A 0.5 kg hockey puck slides across the ice starting with a velocity of 5 m/s. The puck slides and slows for 100 meters under constant acceleration and then stops. a. What is the acceleration of the hockey puck? (.125 m/s2) b. What Kinetic Frictional Force is needed?(0.0625N) c. What is the co‐efficient of friction between the ice and puck?(.013) d. Recalculate a, b & c for a 1 kg hockey puck. (Does the weight change a or c?)
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Ответ:
It would be: x * 125% = 6750
x * 1.25 = 6750 [ 125% = 1.25]
x = 6750 / 1.25
x = 5400
In short, Your Answer would be $5400
Hope this helps!