. A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up
to a maximum height, then returns to the ground. Calculate the rock's momentum as it strikes the
ground.
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Ответ:
p = -8 kg-m/s
Explanation:
Given that,
Initial speed of the rock, u = 8 m/s
Mass of the rock, m = 1 kg
The ball travels up to a maximum height, then returns to the ground.
We need to find the rock's momentum as it strikes the ground. Let v be the final speed of the rock. Its final speed is as same as initial speed i.e. 8 m/s but in negative direction. So
p = mv
p = 1 kg × (-8 m/s)
= -8 kg-m/s
So, the rock's momentum as it strikes the ground is (-8 kg-m/s).
Ответ:
Explanation:
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