A-1.12 μc charge is placed at the center of a conducting spherical shell, and a total charge of +8.65 μc is placed on the shell itself. calculate the total charge on the outer surface of the conductor.

7.53 μC

Explanation: In order to explain this problem  we have to use the gaussian law so we have:

∫E.dS=Qinside/εo we consider a gaussian surface inside the conducting spherical shell so E=0

Q inside= 0 = q+ Qinner surface=0

Q inner surface= 1.12μC so in the outer surface the charge is (8.65-1.12)μC=7.53μC

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Explanation: