joseperez1224
20.02.2020 •
Physics
A 10.0 g insulating sphere with a net charge of +2.0 nC is suspended between two plates of a charged, square capacitorof sides 10 cm and plate separation 10 cm. What is the charge on the top capacitor plate?
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Ответ:
= 4.34 × 10⁻⁶C
Explanation:
Net Force = W - F(electric) = 0
where , F(electric) = qE
qE = qV/d
V = potential between plate
V = Q/C
Q = charge on plate
C = capacitance
C = E₀A / d
F(electric) = qQ/E₀A
W = F(electric)
mg = qQ/E₀A
Q = mgE₀A / q
(A) area of plate = (0.10m)² = 0.01m²
m = 10 × 10⁻³kg
E₀ = 8.85 × 10⁻¹²C²N⁻¹m⁻²
q = 2 × 10⁻⁹c
Q =((10 × 10⁻³)(9.8)(8.85× 10⁻¹²)(0.01)) / (2 × 10⁻⁹)
Q = 4.34 × 10⁻⁶C
Ответ:
Because it's so much simpler and easier to use. The metric system is an improvement over the English system in three major points: One unit of measurement for each physical quantity. No matter from which other quantities of the SI system derived, yields always the same unit.
Explanation: