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cardenas08
14.03.2020 •
Physics
A 140 g air-track glider is attached to a spring. The glider is pushed in 8.2 cm against the spring, then released. A student with a stopwatch finds that 14 oscillations take 14.0 s. Part A What is the spring constant?
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Ответ:
Explanation:
The period of oscillation is given as
T=2π√m/k
Making k subject of the formula
Square both sides of the equation
T²=4π²(m/k)
Cross multiply
T²k=4π²m
Then, divide through by T²
k=4π²m/T²
Where
k is spring constant
m is the mass of the bob
And T is the period of the oscillation
m=140g=0.14kg
14 oscillations takes 14 seconds
Then the period is
T=time/oscillation
T=14/14
T=1sec
Then,
k=4π²m/T²
k=4π²×0.14/1²
k=1.76N/m
Then, the spring constant is 1.76N/m
Ответ: