Bryson2148
11.04.2020 •
Physics
A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 N.
Part A
What is the maximum possible acceleration the truck can give the SUV?
Express your answer to two significant figures and include the appropriate units.
a =
Part B
At this acceleration, what is the force of the SUV's bumper on the truck's bumper?
Express your answer to two significant figures and include the appropriate units.
Fsuv on truck =
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Ответ:
a) , b)
Explanation:
a) The maximum possible acceleration that the truck can give to the SUV is:
b) The equation of equilibrium for the truck is:
The force of the SUV's bumper on the truck's bumper is:
Ответ:
A) the maximum possible acceleration = 3.83 m/s²
B) F(SUV bumper) = 2400 kg *3.83 m/s² = 9192 N = 92 * 10² N
Explanation:
Step 1: Data given
Mass of the truck = 2300 kg
Mass of the SUV = 2400 kg
The maximum forward force on the truck is 18000 N
Step 2: What is the maximum possible acceleration the truck can give the SUV?
Total mass = MAss truck + mass SUV
Total mass = 2300 kg + 2400 kg
Total mass = 4700 kg
Acceleration = Force / mass
The maximum possible acceleration = 18000 N / 4700 kg
the maximum possible acceleration = 3.83 m/s²
Step 3: At this acceleration, what is the force of the SUV's bumper on the truck's bumper?
F = m * a
F(trucks bumper) = 2300 kg *3.83 m/s² = 8809 N
F(SUV bumper) = 2400 kg *3.83 m/s² = 9192 N = 92 * 10² N
Ответ:
Hope This Helps You.