normarismendoza
10.03.2022 •
Physics
A 2kg object starts at rest at the top of a slope which is 10 meters high.
A. What are its initial potential and kinetic energies?
B. How fast is it going when it reaches the bottom of the slope?
C. When the object reaches the bottom of the slope, it continues sliding on the ground. If there is a coefficient of kinetic friction of 0.5 between the object and the ground, What is the force of kinetic friction on the object?
D. Using the force you just calculated and what you know about work and energy, how far will the object travel before stopping (use work and energy, not kinematics)
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Ответ:
The circle is centered at (5, −7) and has a radius of 7.
Step-by-step explanation:
The standard form of the equation of a circle with center (a,b) and radius r is given as:
The given equation is
We rewrite to look like the stay form:
We now compare the two equations to get:
a=5, b=-7 and r=7.
Therefore the circle is centered at (5,-7) and has a radius of 7