Physics: A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

A 3.0kg cat and a 14kg dog exert a force of gravity - id301415384679, moonlightparis9015

Ответ:

muravyevaarina

14.02.2023

Physics

The expression for the gravitational force between two bodies is given by:

$F=G\frac{m_1m_2}{r^2}$

where,

G: Cavendish's constant = 6.67*10-11Nm^2/kg^2

m1 = 3.0kg

m2 = 14kg

Solve the equation above for r:

$\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}$

Hence, the distance between the dog and the car is approximately 1.67m

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Ответ:

owo73

04.07.2021

Physics

Step-by-step explanation:

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A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

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