kelebsessoms89
17.03.2020 •
Physics
A 5.5 g coin sliding to the right at 21.0 cm/s makes an elastic head-on collision with a 16.5 g coin that is initially at rest. After the collision, the 5.5 g coin moves to the left at 10.5 cm/s. (a) Find the final velocity of the other coin. cm/s (b) Find the amount of kinetic energy transferred to the 16.5 g coin. J
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Ответ:
(a) 10.33 cm/s
(b) 0.00088 J
Explanation:
Parameters given:
Mass of first coin, m = 5.5g = 0.0055kg
Mass of second coin, M = 16.5 = 0.0165kg
Initial velocity of first coin, u = 21 cm/s
Final velocity of first coin, v = -10cm/s (because it's in the opposite direction of the initial motion)
Initial velocity of second coin, U = 0 cm/s
(a) Using principle of conservation of momentum:
Total initial momentum = Total final momentum
m*u + M*U = m*v + M*V
U = 0
=> m*u + 0 = m*v + M*V
m*u - m*v = M*V
V = m(u - V) / M
V = 0.0055(21 - (-10)) / 0.0165
V = 0.3333 * 31 = 10.33 cm/s
(b) Kinetic energy is given as:
KE = 0.5 * M * V²
V = 10.33 cm/s = 0.1033 m/s
KE = 0.5 * 0.0165 * 0.1033²
KE = 0.00088 J
Ответ:
Explanation:
Given length is
Circumference of a circle is given as:
a.But the circumference is equal to length of the wire. Therefore circumference as a function of is:
b.Area as function of
Area is calculated as
Rewrite the circumference equation to make r the subject of the formula.
To express area as a function of :-
Therefore area of circle as a function of is