a 5kg-jumps on a table with a mass 30kg.as the dog walk around on top of the table what is the average force that the table applies to the dog?

Problem:

a 5 kg dog jumps on table with a mass of 30 kg what is the average force that the table applies to the dog.

Note:

What ever is the force applied by the dog to the table, it will be the same force exerted by the table to the dog but in opposite direction. Study on the Newton's Third law of motion

Given Data:

m ( mass ) = 5 kg

a ( acceleration ) = 9.8 m/s²

F ( Force ) = ? unknown

Solution:

We will use the formula of Force ( F = m × a ) in order to solve the problem.

F = m × a

= 5 kg × 9.8 m/s²

= 49 kg·m/s²

= 49 N

The table will exert 49 N of Force to the dog

The limiting angle is 7.32x10⁻⁸rad and the separation distance is 8.586x10⁹ rad m

Explanation:

Given data:

λ = 600 nm = 6x10⁻⁷m

D = 10 m

The limiting angle of resolution is equal to:

According Rayleigh expression:

L = 12.4 light year = 1.173x10¹⁷m