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talarleonard0
12.01.2021 •
Physics
A 8.0 cm-diameter horizontal pipe gradually narrows to 4.5 cm. When water flows through this pipe at a certain rate, the gauge pressure in these two sections is 33.0 kPa and 24.0 kPa, respectively. What is the volume rate of flow? in m^3/s
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Ответ:
7.11x10^-3
Explanation:
We are to get the volume rate of flows
1/2pv1² + pl = 1/2pv2²
Such that A1V1 = A2V2
V1 = A2V2/A1
From the attachment I uploaded, we have a formula named equation 1 from which I have plugged in these values
P2 = 33000
P2 = 24000
P = 1000
r2 = 2.25
r1 = 4
When we put these values into the equation,
V2 = 4.47
A2V2 = pi(0.0225)²x4.47
= 7.7x19^-3m³/s
Ответ:
y = 27x ; where x is the number of skateboard decks sold and y is the total amount of profit.
New type material:
y = 32x ;
If Jacob will pursue the new type material, he will earn an additional 5 profit per skate board from his previous scheme.
The additional 5 is the difference of 32 and 27.