Physics: A) a boy is riding on a merry-go-round that rotates at a constant speed. if the merry-go-round makes 3.0 revolutions in 6.0 seconds. what is its angular speed in revolutions/second and in radians/second?

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A) a boy is riding on a merry-go-round that rotates

rusdunkin

14.01.2022

Angular speed = 0.5 revolutions/second = 3.14 rad/s

Explanation:

a) The merry-go-round makes 3.0 revolutions in 6.0 seconds

Time taken for 3 revolutions = 6 s

Time taken for 1 revolution = 6÷3 = 2 s

That is period, T = 2 s

We know that

$\texttt{Angular speed},\omega =\frac{2\pi }{T}$

Substituting

$\texttt{Angular speed},\omega =\frac{2\pi }{2}=3.14rad/s\\\\\texttt{Angular speed},\omega =\frac{2\pi }{2\times 2\pi}=0.5revolutions/s$

Angular speed = 0.5 revolutions/second = 3.14 rad/s

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