A ball is launched upward at an initial speed of 3 m/s. How high did the ball move if it took 4 seconds for the ball to reach its maximum height?

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Ответ:

alonnachambon

19.03.2020

Physics

The force acting on the object at $t = 2\,s$ is $\vec F = (4, 32)\,[N]$ .

Explanation:

Given that object has a constant mass in time, the force acting on the object ( $\vec F$ ), in newtons, is defined by following expression:

$\vec F = m\cdot \vec a$ (1)

Where:

- Mass, in kilograms.

$\vec a$ - Acceleration, in meters per square second.

By definition of acceleration, we know that:

$\vec a = \frac{d}{dt} \vec v$ (2)

Let suppose that given vector velocity is expressed in meters per second. If we know that $m = 2\,kg$ , $\vec v = (2\cdot t, 4\cdot t^{2})\,\left[\frac{m}{s} \right]$ and $t = 2\,s$ , then the force acting on the object is:

$\vec a = (2, 8\cdot t)\,\left[\frac{m}{s^{2}} \right]$

$\vec F = (4, 16\cdot t)\,[N]$

$\vec F = (4, 32)\,[N]$

The force acting on the object at $t = 2\,s$ is $\vec F = (4, 32)\,[N]$ .

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