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jaycobgarciavis
19.02.2020 •
Physics
A battery with an emf of 24.0 V is connected to a resistive load. If the terminal voltage of the battery is 16.1 V and the current through the load is 3.90 A, what is the internal resistance of the battery?
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Ответ:
2.03 Ω
Explanation:
EMF: This can be defined as the potential difference of a cell when it is not delivering any current. The S.I unit of Emf is Volt.
The formula of emf is given as,
E = I(R+r) Equation 1
Where E = Emf, I = current, R = External resistance, r = internal resistance.
Make r the subject of the equation
r = (E-IR)/I Equation 2
Note: From ohm's law, V = IR.
r = (E-V)/I Equation 3
Where V = Terminal voltage
Given: E = 24 V, I = 3.9 A, V = 16.1 V.
Substitute into equation 3
r = (24-16.1)/3.9
r = 7.9/3.9
r = 2.03 Ω
Ответ:
The orbital diagram represents the filling of electrons in the sub levels of an orbit. The filling of the orbitals in sub- levels follow some basic rules and principles.
The orbital diagram of an orbit containing 16 electrons will be as follows:
1s²2s²2p⁶3s²3p⁴
The maximum number of electrons in each sublevel of the orbitals are: 2 electrons for s-sublevel with one orbital 6 electrons for p-sublevel with three orbital 10 electrons for d-sublevel with five orbital 14 electrons for f-sublevel with seven orbital