Physics: A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m . When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant k is 100 N/m. What is the coefficient of kinetic friction between the block and the tabletop

A block with mass 0.50 kg is forced against a horizontal

oudithe3

06.02.2022

μ = 0.41

Explanation:

$\frac{1}{2} kx^2 = \mu mgd$

$\mu = (\frac{1}{2} kx^2)/mgd$

$\mu = (\frac{1}{2} (100)(0.2)^2)/(0.5)(9.81)(1)$

$\mu = 0.41$

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adaneri1234

30.01.2022

so try and use google

Explanation:

yeah man see u.

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