A bow of spring constant 500 N/m is pulled back so that the bowstring extends by 0.50 m. Calculate the elastic potential energy stored in the bow
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Ответ:
The acceleration is the difference of speed: final speed - initial speed, all divided by t.
So:
(80m/s - 0m/s) / 20s = (80m/s)/20s = 4m/s^2