A bowling ball moves with constant velocity from an initial posi-tion of 1.6 m to a final position of 7.8 m in 3.1 s.
(a) What is the position time equation for the bowling ball?
(b) At what time is the ball at the position 8.6 m?
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Ответ:
Responder:
122,500 Pa; 2.45 × 10 ^ -6; 2.94 × 10 ^ -5m
Explicación:
Dado lo siguiente:
Área de sección transversal (A) = 2m ^ 2
Masa (m) = 25000 kg
Módulo de Young = 50 x 10 ^ 9 N / m2
(1) estrés en la columna:
Estrés = Fuerza / Área
F = masa * aceleración debido a la gravedad
F = 25000kg * 9.8m / s ^ 2 = 245,000J
Estrés = 245,000J / 2m ^ 2
Estrés = 122,500 Pa
2) Deformación de la unidad (deformación):
Usando la relación:
Módulo de Young = Estrés / tensión
50 × 10 ^ 9 = 122,500 / CEPA
Cepa = 122500 / (50 × 10^9)
Cepa = 0.00000245
C) Si la altura es de 12 m, ¿cuánto se acorta la columna?
Cepa = extensión / longitud
0.00000245 = extensión / 12
0,00000245 * 12
0,0000294 m