A cannon is fired with an initial horizontal velocity of 20 m/s and initial vertical velocity of 25 m/s. After 3s in the air, the canon hits it’s target. How far away(in meters) was the canon from its target? m

60 m

Explanation:  

After 3 seconds of travel at 20 m/s, the projectile is 3·20 = 60 meters horizontally from the cannon.

__

The vertical height after 3 seconds is 0.9 m, so the straight-line distance from cannon to target is √(60^2 +0.9^2) ≈ 60.007 meters.

Energy provides the possibility or total capacity for any system or object to carry out certain tasks inside a given parameter. Along with that energy is stored in a very specific manner,which is termed as the potential energy or P.E inside each system which again can be utilized by the system to carry out certain task and processes by changing any amount of that stored energy into its dynamic form which is called as the kinetic energy or K.E.

m.g.h=1/2 m.v².As in our daily we can experience the amount of water present in the dams which represents the potential energy for the system. While, the water is again released when ever required by the authority to start the turbines and to generate the optimum amount of energy for different purposes(commercial and domestic usage).Now, the reservoir of water represents the potential energy or P.E of the system.As the molecules are at rest and are present at a certain height,h having some mass,m.As the factor of gravity,g acts more effectively on the molecules of the water.After, which the molecules starts the dynamic motion in a more specified way across the turbines placed beneath the canals of the dam. As these turbines are designed to generates the energy,E when its propellers are forced to rotate by the flow of water. This would create more energy for the commercial and domestic usage.